"He who marches out of step hears another drum." ~ Ken Kesey
I am about to start doing this due to picking up a huge vacuum frame, and logically for me it would be 1.5x the diagonal of the combined art on both screens. I would also think it would be good to have the screens rotated 180 degrees so the light source is mimicking hitting both screens from the same angle/side. See mockup. distance would be 1.5x the red line, centered.
The drawback of your measuring method is an underexposed screen surrounding the image
Quote from: Frog on September 03, 2014, 04:42:39 PMThe drawback of your measuring method is an underexposed screen surrounding the imageI'm not sure I understand. If I take my standard art size of around 13x19, centered on a 23x31 screen, the math adds up to a 40" diagonal if the screens are touching. (13+5)*2 as the bottom "side" of the triangle, so 36^2 + 19^2 = c^2, where c = ~40, then x1.5 = 60 inches away. That should result in fairly even exposure.Al's math is a little off as well. The diagonal on 2 23x31's next to each other (46x31 together) is 55"
I need that old "rule of thumb" info where you x your screen frame size by X to get your light source (distance) for two screens at a time? 23x31's This is for a wall mount exp. I think I recall 40" but that can change based on the screen frame size. Here, we are doing two 23x31's placed horizontal or side by side.Anyone remember what that is?
Dan, you have an in with your comrades at NuArc, bet they could answer precisely...